4[5x-(3x-7)]=2(4x-5)

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Solution for 4[5x-(3x-7)]=2(4x-5) equation:


Simplifying
4[5x + -1(3x + -7)] = 2(4x + -5)

Reorder the terms:
4[5x + -1(-7 + 3x)] = 2(4x + -5)
4[5x + (-7 * -1 + 3x * -1)] = 2(4x + -5)
4[5x + (7 + -3x)] = 2(4x + -5)

Reorder the terms:
4[7 + 5x + -3x] = 2(4x + -5)

Combine like terms: 5x + -3x = 2x
4[7 + 2x] = 2(4x + -5)
[7 * 4 + 2x * 4] = 2(4x + -5)
[28 + 8x] = 2(4x + -5)

Reorder the terms:
28 + 8x = 2(-5 + 4x)
28 + 8x = (-5 * 2 + 4x * 2)
28 + 8x = (-10 + 8x)

Add '-8x' to each side of the equation.
28 + 8x + -8x = -10 + 8x + -8x

Combine like terms: 8x + -8x = 0
28 + 0 = -10 + 8x + -8x
28 = -10 + 8x + -8x

Combine like terms: 8x + -8x = 0
28 = -10 + 0
28 = -10

Solving
28 = -10

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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